3.DESIGN OF YOKE

Taking 20% greater area than that of core for yoke

Area of yoke (A_y)  = 1.2*A_i (take assumption into consideration)

                                 = 1.2*0.0182

                                 = 0.2184m²

Cross area of yoke =Net area/stacking  factor

                                   =0.02184/0.9   =0.0243m²

Taking shape of yoke is rectangular

Here,depth of yoke is equal to depth of core

        D_y= a=0.1567m

Height of yoke(H_y)= A_y/D_y

                                  = 0.0243/0.1567

                                   =0.15507m