3.DESIGN
OF YOKE
Taking 20%
greater area than that of core for yoke
Area of yoke (Ay) = 1.2*Ai (take assumption into
consideration)
= 1.2*0.0182
= 0.2184m2
Cross area of yoke =Net
area/stacking factor
=0.02184/0.9 =0.0243m2
Taking shape of yoke is rectangular
Here,depth of yoke is equal to depth of
core
Dy= a=0.1567m
Height of yoke(Hy)= Ay/Dy
= 0.0243/0.1567
=0.15507m