Finding reactance

FOR LEAKAGE REACTANCE

Now , leakage reactance refers to primary

   X_p=2 *f* *T_p²*L_mt/L_c*(a+(b_p +b_s)/3)

  Where L_mt=length of mean turns

                 L_c=height of winding

                  b_p=radial depth of primary

                   b_s=radial depth of secondary & a= width of insulation

L_mt= d_pt

      = (inside of dia of LV + outside of HV winding)/2

      = *(176.62*293.65)/2

      = 738.72mm

L_c =axial height of primary

L_cs= axial height of secondary

Now, X_p=2* *50*4 *10^-7*2310²*(738.72/363.125)*(15+(47.75+15)/2)

               =198.742 ohm

PU leakage reactance = (3.787*198.742)/11000 = 0.0684